(5v^2+2v)+(-v^2+3v)=-10

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Solution for (5v^2+2v)+(-v^2+3v)=-10 equation: 



(5v^2+2v)+(-v^2+3v)=-10

We move all terms to the left:

(5v^2+2v)+(-v^2+3v)-(-10)=0

We add all the numbers together, and all the variables

(-v^2+3v)+(5v^2+2v)+10=0

We get rid of parentheses

-v^2+5v^2+3v+2v+10=0

We add all the numbers together, and all the variables

4v^2+5v+10=0

a = 4; b = 5; c = +10;
Δ = b2-4ac
Δ = 52-4·4·10
Δ = -135
Delta is less than zero, so there is no solution for the equation

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